Seenemo wrote:
Hi everyone, firs time builder here! I have looked around online and through this forum, but I could not find an exact way/best way to wire this. I have some experience with electrical diagrams but it is basic.
My parts list:
-12w (red orange) 350mA max 2.6v (can someone confirm this)
-18650 battery + battery holder
-Recharge port with charger and kill key
-Sound board champion saberCore 2.0
-Hi-Bass speaker
-Switch
I have found :
https://saberforgeforum.com/forum/adaptive-saber-parts/11817-mod-add-charge-port-and-lighted-switch-to-asp
This seems to be the most promising, but I dont get why the positive line in-between the charge port and the switch has a resistor.
My second question is how do I wire the LED board?
I have seen 2-3 different setups for the led and am more confused than when I started.
Do 1-2-4-5 go in series with 1 ground wire leaving?
I also read that the 2 positives are already connected together, Is this true? and if that is the case could I have just one positive wire leaving?
Any help would be appreciated!
I'll answer your questions in order.
The resistor between the switch and the charge port is only necessary if you have a lit AV switch, as is the lead to the "negative" terminal on the switch. This resistor should be sized based on the battery voltage and switch LED forward voltage such that the current through the LED is 20mA.
For the LED star, the positive pads should be connected on a Saberforge star. For the negatives, there are two possibilities. One is that all of the negatives are separate, allowing control of each individual color, or 1 and 2 are interconnected and 4 and 5 are interconnected. This is typical of most SF stars, but it would probably be best practice to check whether the pads are connected using the continuity function on a multimeter. I've attached an old sketch I made of the more common scenario.
You'll only require one positive lead in either configuration, and depending on the wiring method and if you jump the pads you'll probably end up with 1, 2, or 4 negative leads that are each resistored separately. Here's some images of the wiring on an old 12W red module:
You can see how the negatives control each pair of LEDs, then each pair has its own 1 ohm resistor (in the second picture I unintentionally broke the wire from the solder joint on the top pad, but you can see where it was connected). The leads are connected south of the resistors to simplify the wiring back to the LED contact on the board.